Find the co-ordinates of the points on the curves given by the following equation at which the gradient has the given value: y = xTo solve this, I found the derivate of the function: dy/dx = 2x - 3 and equated it to 1 and solved for x, giving me x = 2. Is this correct? How do I present my answer in terms of coordinates? What if there are two answers for x?^{2}- 3x + 1, gradient = 1.

Also, I'm asked in a different question to differentiate f(x) = 5 by first principles. I know that the answer is zero, but how do I show working out to prove it?

Thanks in advance.