How would I find the Talyor or Laurent series around the parameter c of the function:
$\displaystyle R(z)=\frac{z-c}{z^2}$
Any help would be great.
Let w = z – c. Then $\displaystyle \frac{z-c}{z^2} = \frac w{(c+w)^2} = \frac w{c^2}\Bigl(1+\frac wc\Bigr)^{-2}$, which you can expand as a binomial series in powers of w/c = (z-c)/c.