Originally Posted by

**Mukilab** Thanks for your help topsquark.

Is the dx you are using what is usually at the end of an integration (you are integrating with respect to d) or is it just a constant? If it is the former, I had no idea you're allowed to put it into the equation that you are integrating.

Assuming it is just a constant, yofur du/u would give you d. Integrating this would give you x.

Therefore for my integral above, would this be correct?:

$\displaystyle \int \frac {x+2}{(x+1)(x-1)} dx$ = $\displaystyle \frac {3}{2} \int \frac {1}{x-1} dx - \frac {1}{2} \int \frac {1}{x+1} dx$ = $\displaystyle 1$