Yes the constant multiple rule applies here, in fact, it would be easiest if you take out -2/3 as a factor.
Find s'(t).
Does the constant multiple rule apply here?
s(t) = [-2(2-t) * sqrt{1+t}]/3
I pulled out 1/3 but my answer is nothing like the book's answer.
Applying the constant rule, the problem now looks like this:
s(t) = (1/3) times [-2(2-t) * sqrt{1+t}]
The fraction (1/3) comes along for the ride.
I then know to apply the product rule to everything else.
The answer is (t)/sqrt{1+t}. Can someone work out this problem for me? I would love to see the steps. I never post a question in this forum without working out the problem many times on my own. Please, help. Thank you.
Ok, so you apply the product rule to .
You should get . The first term you can multiply top and bottom by to get in the denominator, and the second will have it when you take the derivative. So what does each term have in the numerator?
- Hollywood
I'll try this one again tomorrow (my day off). I am going chapter by chapter in my single variable calculus text which covers calculus 1 and 2. I always wanted to learn calculus 1-3. Why take out a loan and run myself into debt?
The internet makes it possible for me to learn calculus.
If I can go as far as mutivariable calculus on my own and learn it sufficiently well, it is a great accomplishment. The next chapter is Implicit Differentiation.