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Math Help - indefinite integral

  1. #1
    Junior Member
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    indefinite integral

    The original problem:
    <br />
\int 6/(1-2x)^3 dx<br />

    I have got it down to this but for some reason I have no idea what to do with the 1/u^3, can someone please help?
    <br />
-3 \int 1/u^3 du<br />

    thank you
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  2. #2
    Math Engineering Student
    Krizalid's Avatar
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    You almost got it!

    \frac1{u^3}=u^{-3}.

    Apply the power rule for integrals.
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  3. #3
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    oh wow i feel like an idiot! thanks for your time
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  4. #4
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    Did you basically get du=-2 and u=1-2x?

    since you had a 6 in the numerator you pulled it out and put it in front of the integration symbol and replaced it with the -2 that you needed in that spot. Then, I guess you divided the 6 that was outside the integration symbol by
    -2 to give you the -3?
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