# Math Help - indefinite integral

1. ## indefinite integral

The original problem:
$
\int 6/(1-2x)^3 dx
$

I have got it down to this but for some reason I have no idea what to do with the 1/u^3, can someone please help?
$
-3 \int 1/u^3 du
$

thank you

2. You almost got it!

$\frac1{u^3}=u^{-3}.$

Apply the power rule for integrals.

3. oh wow i feel like an idiot! thanks for your time

4. Did you basically get du=-2 and u=1-2x?

since you had a 6 in the numerator you pulled it out and put it in front of the integration symbol and replaced it with the -2 that you needed in that spot. Then, I guess you divided the 6 that was outside the integration symbol by
-2 to give you the -3?