Originally Posted by

**rhcprule3** Im supposed to find the slope of the tangent line at the point (3,2) for the function (4x^2+2y^2)^2-4x^2y=1864

So here's what I did

2(4x^2+2y^2)(8x+4yy')-4(2xy+x^2y')=0

(8x^2+4y^2)(8x+4yy')-8xy-4x^2y'=0

64x^3+32x^2yy'+32y^2x+16y^3y'-8xy-4x^2y'=0

y'(32x^y+16y^3-4x^2)=-64x^3-32y^2x+8xy

y'=(-64x^3-32y^2x+8xy)/(32x^2y+16y^3-4x^2)

So I plugged in the x and y values to get the slope but webwork says its incorrect, I thought I smacked the bullseye dead center but apparently I messed up somewhere... if anyone can take a look and see what mistakes I made I would appreciate it! Thank You!