1. ## Double Integrals Problem

This is the question and the integral i setup. But its wrong. Not sure where i went wrong.

This is the equation that I setup

$\int_0^\frac{\pi}{2} \int_0^\pi$ $sin(x)sin(y)dxdy$

I also tried setting x range $-\pi$ to $\pi$ but i kept getting zero.

2. ## Re: Double Integrals Problem

Hey tastylick.

Hint: Your x limits should be from -pi to +pi (as you have suggested). Using this gives us

Integral [0,pi/2] sin(y)[-cos(pi) + cos(-pi)]dy
Integral [0,pi/2] sin(y)[-1-1]
Integral [0,pi/2[ -2*sin(y)
= 2[cos(pi/2) - cos(0)] = -2.