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Math Help - Double Integrals Problem

  1. #1
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    Double Integrals Problem

    This is the question and the integral i setup. But its wrong. Not sure where i went wrong.

    Double Integrals Problem-screen-shot-2013-10-11-10.43.21-pm.png



    This is the equation that I setup

    \int_0^\frac{\pi}{2} \int_0^\pi  sin(x)sin(y)dxdy

    I also tried setting x range -\pi to \pi but i kept getting zero.
    Last edited by tastylick; October 11th 2013 at 08:13 PM.
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  2. #2
    MHF Contributor
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    Re: Double Integrals Problem

    Hey tastylick.

    Hint: Your x limits should be from -pi to +pi (as you have suggested). Using this gives us

    Integral [0,pi/2] sin(y)[-cos(pi) + cos(-pi)]dy
    Integral [0,pi/2] sin(y)[-1-1]
    Integral [0,pi/2[ -2*sin(y)
    = 2[cos(pi/2) - cos(0)] = -2.
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