This is the question and the integral i setup. But its wrong. Not sure where i went wrong.

Attachment 29448

This is the equation that I setup

I also tried setting x range to but i kept getting zero.

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- Oct 11th 2013, 08:04 PMtastylickDouble Integrals Problem
This is the question and the integral i setup. But its wrong. Not sure where i went wrong.

Attachment 29448

This is the equation that I setup

I also tried setting x range to but i kept getting zero. - Oct 11th 2013, 11:50 PMchiroRe: Double Integrals Problem
Hey tastylick.

Hint: Your x limits should be from -pi to +pi (as you have suggested). Using this gives us

Integral [0,pi/2] sin(y)[-cos(pi) + cos(-pi)]dy

Integral [0,pi/2] sin(y)[-1-1]

Integral [0,pi/2[ -2*sin(y)

= 2[cos(pi/2) - cos(0)] = -2.