Hi!

I am not sure how to go about the following.

Let $\displaystyle f(x) = \sqrt{x^2-x}$.

Find any $\displaystyle x$ values where the slope of the line tangent to the graph of $\displaystyle f(x)$ would be equal to $\displaystyle 0$.

Would I simply find the roots: x = 0; x = 1?

Those are the x-values where the tangent is 0.