Implicit differentiation find points where slope is ___

I have two problems dealing with this. I am getting myself all screwed up and could use help.

the first is at what points is the slope of the tangent line equal to 1 on [x^2/9] + [y^2/16] = 1

So I got the derivative dy/dx = -[16x/9y]

so now I solve for -[16x/9y] = 1 ; correct?

The other question is find the points at which the tangent is horizontal for

x^3 + 4x^2 +xy^2 - 4y^2 = 0

I got dy/dx = [3x^2 + 8x +y^2]/6

so same thing, solve for dy/dx to be zero?

Re: Implicit differentiation find points where slope is ___

Quote:

Originally Posted by

**Jonroberts74** I have two problems dealing with this. I am getting myself all screwed up and could use help.

the first is at what points is the slope of the tangent line equal to 1 on [x^2/9] + [y^2/16] = 1

So I got the derivative dy/dx = -[16x/9y]

so now I solve for -[16x/9y] = 1 ; correct?

Yes, when you have , you solve for one of the variables (either x or y) and plug it back into the original equation for the eclipse: e.g. , so .

Quote:

Originally Posted by

**Jonroberts74** The other question is find the points at which the tangent is horizontal for

x^3 + 4x^2 +xy^2 - 4y^2 = 0

I got dy/dx = [3x^2 + 8x +y^2]/6

so same thing, solve for dy/dx to be zero?

Yes, you do the same thing to get a relationship between x and y. But you may want to check what you got for the derivative once more. You should have gotten .

Re: Implicit differentiation find points where slope is ___

ah yeah, oops. got the correct derivative the second time around.

Re: Implicit differentiation find points where slope is ___

Quote:

Originally Posted by

**Jonroberts74** ah yeah, oops. got the correct derivative the second time around.

Also for that second problem, when you plug in zero for the derivative, you can solve for since the original formula does not have any terms with only in them. This way, you avoid square roots.

Re: Implicit differentiation find points where slope is ___

Can you show me how you would solve to get that, I'm not getting it. And I tried using wolfram but it's losing me. It's saying multiple both sides by the denominator to clear the fraction. Which I understand in other problems fine but it's confusing me with this.

thanks.

Re: Implicit differentiation find points where slope is ___

Set the derivative equal to zero and solve for :

Plug this into the original equation :

Re: Implicit differentiation find points where slope is ___

okay perfect, then input the value of x into the original to find the y point. correct?

Re: Implicit differentiation find points where slope is ___

Or plug them into

Re: Implicit differentiation find points where slope is ___

I was just going to ask that haha

Re: Implicit differentiation find points where slope is ___

should have mentioned there was a diagram showing that the x value wouldn't be exceeding 4 for the the right value for x is x = 2 - 2sqrt5

so plugging that in I get

y^2 = -3[2-2sqrt5] - 8[2 - 2sqrt5]

distribute those out for y = sqrt[-22 + 22sqrt5] but thats not the right answer. what am I missing?

Re: Implicit differentiation find points where slope is ___

the answer comes out to (2 - 2sqrt5, 2 +/- sqrt[10sqrt(5) - 22])

Re: Implicit differentiation find points where slope is ___

oh I missed a square. try this now

Re: Implicit differentiation find points where slope is ___

nope, still not getting it.

Re: Implicit differentiation find points where slope is ___

I get to -56 +40sqrt5 = y^2 from in the value of x into y^2 = -3x^2 -8x

Re: Implicit differentiation find points where slope is ___

solved, got it, thank you