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Math Help - ln Derivative Problem

  1. #1
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    ln Derivative Problem

    h(x) = \ln(x + \sqrt{x^{2} - 9})

    h(x) = \ln(x + (x^{2} - 9)^{1/2})

    h'(x) = \ln(1 + [\dfrac{1}{2}(u)^{-1/2} du]

    h'(x) = \ln(1 + [\dfrac{1}{2}(u)^{-1/2} 2x]

    h'(x) = \ln(1 + [x (x^{2} - 9)^{1/2} ] ?? What now?
    Last edited by Jason76; October 7th 2013 at 09:16 PM.
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  2. #2
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    Re: ln Derivative Problem

    Quote Originally Posted by Jason76 View Post
    h(x) = \ln(x + \sqrt{x^{2} - 9})

    h(x) = \ln(x + (x^{2} - 9)^{1/2})

    h'(x) = \ln(1 + [\dfrac{1}{2}(u)^{-1/2} du]

    h'(x) = \ln(1 + [\dfrac{1}{2}(u)^{-1/2} 2x]

    h'(x) = \ln(1 + [x (x^{2} - 9)^{1/2} ] ?? What now?

    You applied the derivative incorrectly:

    y = log(u) ==> y'= u'/u
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  3. #3
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    Re: ln Derivative Problem

    Hi Jason76 !
    See attachment
    Attached Thumbnails Attached Thumbnails ln Derivative Problem-mistake.jpg  
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