# Thread: Evaluate the definite integral...integrating by parts

1. ## Evaluate the definite integral...integrating by parts

So, I have got another problem and can't figure out where is my mistake,

I have the following integral $\int_{2}^{5} t^{4}ln(2t)dt$, I considered $u = ln(2t) => u' = \frac{1}{2t}; v' = t^{4} => v = \frac{t^{5}}{5}$

and proceeded as follows: $\left( \frac{t^{5}}{5}ln(2t) \right) - \int\frac{1}{2t}\frac{t^{5}}{5}dt =$ here, I considered that I can do some simplifications and

obtained that $\left( \frac{t^{5}}{5}ln(2t) \right) - \int\frac{1}{10} t^{4}dt = \left( \frac{t^{5}}{5}ln(2t) \right) - \frac{t^{5}}{50} =$,

but by evaluating it further and doing all the math I don't get the correct answer,

I saw that and thought that I can't do the simplifications since they are still $u'$ and $v$,

so, I considered them separately, even though it seems wrong for me $\left( \frac{t^{5}}{5}ln(2t) \right) - \frac{t^{6} ln|2t|}{30}$ , but this also, as I expected, wrong,

please, can someone show me the mistake(s)?

2. ## Re: Evaluate the definite integral...integrating by parts

Originally Posted by dokrbb
So, I have got another problem and can't figure out where is my mistake,

I have the following integral $\int_{2}^{5} t^{4}ln(2t)dt$, I considered $u = ln(2t) => u' = \frac{1}{2t}; v' = t^{4} => v = \frac{t^{5}}{5}$

and proceeded as follows: $\left( \frac{t^{5}}{5}ln(2t) \right) - \int\frac{1}{2t}\frac{t^{5}}{5}dt =$ here, I considered that I can do some simplifications and

obtained that $\left( \frac{t^{5}}{5}ln(2t) \right) - \int\frac{1}{10} t^{4}dt = \left( \frac{t^{5}}{5}ln(2t) \right) - \frac{t^{5}}{50} =$,

but by evaluating it further and doing all the math I don't get the correct answer,

I saw that and thought that I can't do the simplifications since they are still $u'$ and $v$,

so, I considered them separately, even though it seems wrong for me $\left( \frac{t^{5}}{5}ln(2t) \right) - \frac{t^{6} ln|2t|}{30}$ , but this also, as I expected, wrong,

please, can someone show me the mistake(s)?
did you apply the limits 2 and 5 correctly? also, the derivative u' is 1/t, not 1/2t

3. ## Re: Evaluate the definite integral...integrating by parts

Originally Posted by votan
did you apply the limits 2 and 5 correctly?
with my first evaluation I get 1368,383397, with the second one I have 233,9377581 (but I suppose this one is a priori wrong, so...),

4. ## Re: Evaluate the definite integral...integrating by parts

[QUOTE=dokrbb;799460]I considered $u = ln(2t) => u' = \frac{1}{2t}$

Consider it further

Edit: sorry, votan did say that!

5. ## Re: Evaluate the definite integral...integrating by parts

[QUOTE=tom@ballooncalculus;799489]
Originally Posted by dokrbb
I considered $u = ln(2t) => u' = \frac{1}{2t}$

Consider it further

Edit: sorry, votan did say that!
and if you were answering without sarcasm...

6. ## Re: Evaluate the definite integral...integrating by parts

never mind, I figured it out,