# x^x

• March 16th 2006, 01:11 PM
x^x
How do I show that x^x->1 as x->0?
• March 16th 2006, 01:19 PM
rgep
You could try showing that $x \log x \rightarrow 0$ as $x \rightarrow 0$. If the limit exists it must be zero: consider $x = 2^{-n}$.
• March 16th 2006, 01:49 PM