Find the speed of the football when it is released.

What am I doing wrong...

**The quarterback of a football team releases a pass at a height of 8 feet above the playing field, and the football is caught by a receiver 38 yards directly downfield at a height of 4 feet. The pass is released at an angle of **https://fsulearn.ferris.edu/courses/...es/mc021-1.jpg**with the horizontal. Find the speed of the football when it is released. Round your answer to three decimal places.**

Formula used: (Vo Cosθ)t **i + ****[ h+(Vosinθ)t - ˝gt˛]**** j**

OK so. My method to solve this was to solve the X portion for t with respect to Vo and then plug t into the y portion to solve for Vo. 38 yards = 114 ft

Vo cosθ t = x

Vo cos(45) t = 114

t=114/Vo cos45

t= 114√2Vo

**[ h+(Vosinθ)t - ˝gt˛] = y**

4= 8+(Vo sin45)t -16t^{2 }-4 = (Vo sin45)( 114√2Vo) -16( 114√2Vo)^{2 }-4 = 114Vo^{2} -16( 25992)Vo^{2 }-4 = 114Vo^{2} -415872Vo^{2}-4 = (114-415872)Vo^{2 }-4 = -415758Vo^{2 }-4/-415758 = Vo^{2 }^{Vo= }√(2/207879)Vo = .003102

Possible answers;

| a. | 19.462 feet per second |

| b. | 33.169 feet per second |

| c. | 118.732 feet per second |

| d. | 59.366 feet per second |

| e. | 190.165 feet per second |

What am I doing wrong!!

This is killing me and i have quiz on it tomorrow

Re: Find the speed of the football when it is released.

Quote:

Originally Posted by

**shmiks** **The quarterback of a football team releases a pass at a height of 8 feet above the playing field, and the football is caught by a receiver 38 yards directly downfield at a height of 4 feet. The pass is released at an angle of **https://fsulearn.ferris.edu/courses/...es/mc021-1.jpg with the horizontal. Find the speed of the football when it is released. Round your answer to three decimal places.

Check the units... Otherwise the solution method is sound.

-Dan