I have the following integral $\displaystyle \int \frac{-8x}{(x+2)^\frac{1}{4}}$ which I`m supposed to evaluate by substitution, but I can't wrap my mind around this,

I tried $\displaystyle u = {(x+2)^{-\frac{1}{4}}}$ but in this case $\displaystyle \frac{du}{dx} = -\frac{1}{4}*{(x+2)^{-\frac{5}{4}}}$, and is getting more complicated...

could you give me a hint, or maybe the substitution is not even possible here?