Originally Posted by

**junkwisch** So we are having a holiday right now and I decide to go over the math which I'm bad at "partial fraction"

The question is my exercise book is $\displaystyle (x^3+3x+7)sin^2(y)\frac{dy}{dx}=x^2+1 for, y(-1)=0 $

so I work around with the algebra a bit and got the equation to become

$\displaystyle \int sin^2(y)dy=\int\frac{x^2+1}{x^3+3x+7}dx$

the problem is that I wasn't sure how to integrate $\displaystyle \frac{x^2+1}{x^3+3x+7}$ this since I cannot factorise the denominator into somethign like (x^2+A)(x+B)

so how does one set up $\displaystyle \frac{x^2+1}{x^3+3x+7}$ for partial fractions

Best Regards

Junks