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Math Help - Find a vector field F(x,y) in R^2 such that f is perpendicular to the field ...

  1. #1
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    Find a vector field F(x,y) in R^2 such that f is perpendicular to the field ...

    Find a vector field F(x,y) in R^2 such that F is perpendicular to the field (x+y)i-(1+x^2)j at every point.

    I'm thinking: Let F = ( f1, f2) be the components of the field where f1 and f2 are functions of x,y. Call (x+y)i-(1+x^2)j field G = (g1,g2) where g1 = (x+y), g2=(-1-x^2). Then F dot G = 0 = ||F|||G||cos(Theta). Will this work?
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  2. #2
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    Re: Find a vector field F(x,y) in R^2 such that f is perpendicular to the field ...

    Almost,
    F.G= f1g1+f2g2=0
    In order for f1g1=-f2g2 g1 should equal f2 and g2 should equal -f1
    Thanks from topsquark
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