1. ## definite integration no.8

p218 ex22a q 31

2. Originally Posted by afeasfaerw23231233
p218 ex22a q 31
You can put this into a more "standard" form by multiplying the top and bottom of the integrand by $1 - sin(x)$.

-Dan

3. $\int {\frac{{1 - t^2 }}{{1 + t^2 }}\,dt} = \int {\frac{{2 - (1 + t^2 )}}{{1 + t^2 }}\,dt} = 2\int {\frac{1}{{1 + t^2 }}\,dt} - \int {dt} .$

I think this way takes less time.