p218 ex22a q 31

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- Nov 7th 2007, 12:36 AMafeasfaerw23231233definite integration no.8
p218 ex22a q 31

- Nov 7th 2007, 03:26 AMtopsquark
- Nov 7th 2007, 03:59 AMKrizalid
$\displaystyle \int {\frac{{1 - t^2 }}{{1 + t^2 }}\,dt} = \int {\frac{{2 - (1 + t^2 )}}{{1 + t^2 }}\,dt} = 2\int {\frac{1}{{1 + t^2 }}\,dt} - \int {dt} .$

I think this way takes less time.