I'm not sure how to go about finding the solution, so any help will be much appreciated: q'=0.14q q(0)=-5 q(x)=? q(7)=?
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Originally Posted by blurain I'm not sure how to go about finding the solution, so any help will be much appreciated: q'=0.14q q(0)=-5 q(x)=? q(7)=? $\displaystyle q' = 0.14q$ $\displaystyle \Rightarrow \frac {q'}q = 0.14$ $\displaystyle \Rightarrow \ln q = 0.14x + C$ $\displaystyle \Rightarrow q(x) = Ae^{0.14x}$ now use your initial data (that is, q(0) = -5) to solve for A. then you can answer the rest
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