I understand that means plugged into the function (at it's value). However we don't have the function, only a chart. How to get around this?
Last edited by Jason76; August 26th 2013 at 06:38 PM.
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Hey Jason76. Hint: Use the chain rule where h'(x) = g'(x)f'(g(x)) (What x corresponds to the one in line with h'(30))?
Originally Posted by chiro Hey Jason76. Hint: Use the chain rule where h'(x) = g'(x)f'(g(x)) (What x corresponds to the one in line with h'(30))? The answer is , but the chart seems to be saying If you look at the line for at , then you get
g(30) = 20, f(20) = 8 with derivatives: g'(30) = 10, f'(20) = 5 so this means h'(30) = g'(30)*f'(20) = 10*5 = 50.
Originally Posted by chiro g(30) = 20, f(20) = 8 with derivatives: g'(30) = 10, f'(20) = 5 so this means h'(30) = g'(30)*f'(20) = 10*5 = 50. ok thanks. Makes sense.
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