I understand that $\displaystyle f(g(x))$ means $\displaystyle g(x)$ plugged into the function $\displaystyle f$ (at it's $\displaystyle x$ value). However we don't have the function, only a chart. How to get around this?
Last edited by Jason76; Aug 26th 2013 at 05:38 PM.
Hint: Use the chain rule where h'(x) = g'(x)f'(g(x)) (What x corresponds to the one in line with h'(30))?
The answer is $\displaystyle 50$, but the chart seems to be saying $\displaystyle 30$ If you look at the line for $\displaystyle g(x)$ at $\displaystyle 30$, then you get $\displaystyle 20$