Since you found the minimum, and given that a(t) is a parabola, you know that the function increases as you move away from t=1. So simply check the boundary points of t=0 and t=3.
Given:
What is the max acceleration on the interval: ? - Answer = 21
Logic: When the graph has a maximum value, then it's derivative will be . So of at maximum points. You simply find which of these points lies within the given interval.
So, - Note is random made up term.
- Solve for t. See which values like within
and would be our acceleration value after plugging into
Now test for max or min using 2nd derivative test:
That is positive so our answer of is a minimum and the graph is concave up.
In this case how to find the maximum?