After flipping it to get dT/dt, how would I solve the integral and rearrange for T? Help appreciated.

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- Aug 19th 2013, 12:43 AMiamapineappleHow to solve dt/dT = -K(T - 5) + H for T?
After flipping it to get dT/dt, how would I solve the integral and rearrange for T? Help appreciated.

- Aug 19th 2013, 01:03 AMiamapineappleRe: How to solve dt/dT = -K(T - 5) + H for T?

Is this correct? - Aug 19th 2013, 02:03 AMibduttRe: How to solve dt/dT = -K(T - 5) + H for T?
- Aug 19th 2013, 03:02 AMProve ItRe: How to solve dt/dT = -K(T - 5) + H for T?
- Aug 19th 2013, 04:05 AMiamapineappleRe: How to solve dt/dT = -K(T - 5) + H for T?
Shoot, sorry, the equation was dT/dt = the equation

- Aug 19th 2013, 06:12 AMHallsofIvyRe: How to solve dt/dT = -K(T - 5) + H for T?
IF the problem was then write it as and integrate both sides.

IF it was then write it as and integrate both sides.

(To integrate on the left, let u= T- 5- H/K.) T will be an exponential of t.