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Math Help - Help slope calculation understanding

  1. #1
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    Help slope calculation understanding

    Hi, I am new to this website, and learning a bit of math on my own, Need help on this slope calculation, I am looking to learn where the products are coming from in the equation. here is the question. Electrical differential slope calculation ( w1 is winding 1 and w2 is winding 2 )
    SLP1 (slope 1 = 20% or 0.2) IOP = (Iw1 - Iw2) IRT = (Iw1 + Iw2)/2
    Equation solve IOP=SLP1/100 x IRT
    Step 1 -> IOP = 0.2/100 x IRT
    Step 2 -> (Iw1 - Iw2) = 0.2 x (Iw1 + Iw2)/2
    Step 3 -> 2 x (Iw1 - Iw2) = 0.2 x (Iw1 + Iw2)
    Step 4 -> 2 x (Iw1 - Iw2)/0.2 = (Iw1 + Iw2)
    Step 4 -> 10 x (Iw1 - Iw2) = (Iw1 + Iw2) -> question 1 -> where did the 10 come from?
    Step 5 -> 10Iw1 10Iw2 = Iw1 +Iw2
    Step 6 -> 10Iw1 Iw1 = Iw2 + 10Iw2
    Step 7 -> 9Iw1 = 11Iw2 -> question 2 -> I get that 10 -1 = 9 and 10 +1 = 11, but why . is this allowed?
    Step 8 -> Iw1 = 11/9Iw2
    Step 9 -> Iw1 = 1.222Iw2
    Step 10 -> 9Iw1 = 11Iw2
    Step 11 -> 9/11Iw1 = w2
    Step 12 -> Iw2 = 0.818Iw1
    Fin! With 2 questions This is for a relay application in per unit, but I am having trouble understanding the theory behind the process here. any help is apprecitated
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  2. #2
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    Re: Help slope calculation understanding

    Quote Originally Posted by rumor84 View Post
    ...
    Step 4 -> 2 x (Iw1 - Iw2)/0.2 = (Iw1 + Iw2)
    Step 4 -> 10 x (Iw1 - Iw2) = (Iw1 + Iw2) -> question 1 -> where did the 10 come from?
    step 4: \frac{2 \cdot (I_{w_1}-I_{w_2})}{0.2} = ....

    and what value has \frac2{0.2} ?


    Step 5 -> 10Iw1 10Iw2 = Iw1 +Iw2
    Step 6 -> 10Iw1 Iw1 = Iw2 + 10Iw2
    Step 7 -> 9Iw1 = 11Iw2 -> question 2 -> I get that 10 -1 = 9 and 10 +1 = 11, but why . is this allowed?
    ...
    a) a more real life example: If you have 10 candies and eat one, how many candies are left?
    b) a more formal attempt:

    10I_{w_1} = 10 \cdot I_{w_1}

    That means that you have in this line

    10I_{w_1} - I_{w_1}

    two summands with a common factor:

    10 \cdot I_{w_1} - 1 \cdot I_{w_1} = I_{w_1}(10-1) = 9I_{w_1}
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  3. #3
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    Re: Help slope calculation understanding

    Ohhh, I see it now, and couldn't be more clear. thank you for the help!
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