I've just started this unit at university.
A question was to solve this ODE:
y' = y
Why is it that the answer is not y= y^2/2 + c,
but instead y= ce^x
also should it actually be written as y(x)=ce^x, or does that not matter?
Is there an algebraic approach to do this question? I put it in wolfram, and the final two steps were:
y(x) = e^(x+c)
=> y(x) = ce^x
I don't quite understand how that simplifies.
Any help is appreciated, thanks!