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Math Help - Parabola Trignometry

  1. #1
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    Parabola Trignometry

    Hi, could someone please help me with part (a) of this question. I understand everything except that part...

    Thanks heaps.
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  2. #2
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    Re: Parabola Trignometry

    Since it is in calculus i presume we can use differential.
    equation of the parabola is
    y^2 = 4px.
    dy/dx = 2p/y
    slope of tangent at the point ( x0, y0) will be = 2p/y0
    That gives us the value of tan beta.
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  3. #3
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    Re: Parabola Trignometry

    Quote Originally Posted by Vishak View Post
    Hi, could someone please help me with part (a) of this question. I understand everything except that part...
    Note that L is the tangent line to y^2=4x at (x_0,y_0).

    \beta is the angle L makes with the positive x-axis. So the slope of L is \tan(\beta).

    But that slope is \\2yy'=4p\\y'=\frac{2p}{y}~.
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    Re: Parabola Trignometry

    Thanks heaps guys! Really appreciate it.
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