Hi, could someone please help me with part (a) of this question. I understand everything except that part... Thanks heaps.
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Since it is in calculus i presume we can use differential. equation of the parabola is y^2 = 4px. dy/dx = 2p/y slope of tangent at the point ( x0, y0) will be = 2p/y0 That gives us the value of tan beta.
Originally Posted by Vishak Hi, could someone please help me with part (a) of this question. I understand everything except that part... Note that is the tangent line to at . is the angle makes with the positive -axis. So the slope of is . But that slope is
Thanks heaps guys! Really appreciate it.
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