Dear All!

Please, I can't solve:

The result should be

Can someoe help?

Many thanks!

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- July 27th 2013, 11:20 AMBoof'(e^2(2x-1))
Dear All!

Please, I can't solve:

The result should be

Can someoe help?

Many thanks! - July 27th 2013, 12:08 PMPlatoRe: f'(e^2(2x-1))
- July 28th 2013, 06:30 AMBooRe: f'(e^2(2x-1))
Hello

Please,I don't understand this.

What rule is that?\

Many thanks!!! - July 28th 2013, 07:01 AMmuddywatersRe: f'(e^2(2x-1))
you have probably previously learned how to differentiate ? it will be

try using the same idea to differentiate the question u are doing now (both and are composite functions) - July 28th 2013, 06:48 PMwonderingRe: f'(e^2(2x-1))
I don't know if this way is easier to understand-

let u = 2x-1

that's the chain rule they are talking about

where so

- July 31st 2013, 08:00 AMBooRe: f'(e^2(2x-1))
That's it!THANKS!!!!