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Math Help - GPS hyperbola question

  1. #1
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    GPS hyperbola question

    A bit of a crazy question and in completely lost.

    I fully understand how to graph hyperbolas but how do I deal with the .001 second variable?

    ThanksGPS hyperbola question-imageuploadedbytapatalk-21374038141.777315.jpg
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  2. #2
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    Re: GPS hyperbola question

    Quote Originally Posted by minneola24 View Post
    A bit of a crazy question and in completely lost.

    I fully understand how to graph hyperbolas but how do I deal with the .001 second variable?

    ThanksClick image for larger version. 

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    1. A time difference of 0.001 s correspond to a distance of 186 miles.

    2. To determine the x-coordinate of the ship's position use the definition of the hyperbola as the locus of points whose difference of the distances to two fixed points is a constant. You have to solve for x:

    \sqrt{(-150-x)^2+75^2} - \sqrt{(150-x)^2+75^2} =186

    3. For confirmation only: I've got x \approx 110.3
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