# Thread: GPS hyperbola question

1. ## GPS hyperbola question

A bit of a crazy question and in completely lost.

I fully understand how to graph hyperbolas but how do I deal with the .001 second variable?

Thanks

2. ## Re: GPS hyperbola question

Originally Posted by minneola24
A bit of a crazy question and in completely lost.

I fully understand how to graph hyperbolas but how do I deal with the .001 second variable?

Thanks
1. A time difference of 0.001 s correspond to a distance of 186 miles.

2. To determine the x-coordinate of the ship's position use the definition of the hyperbola as the locus of points whose difference of the distances to two fixed points is a constant. You have to solve for x:

$\sqrt{(-150-x)^2+75^2} - \sqrt{(150-x)^2+75^2} =186$

3. For confirmation only: I've got $x \approx 110.3$