Can't seem to get this question.
find dy/dx of y=-log(base,e)(cosx)
i get the expression to (-cosx/x)+log(base,e)+sinx. But I don't know how to take it any further.
the answer is tanx
any help appreciated, thx
What you need is the product rule. So d/dx (f(g(x))) is f'(g) x g'(x). log'(f) is 1/f, d/dx(cos) is -sin,
so you have -sin/-cos , which is tan.
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