Yes, that will work. You will have two integrals, , which is easy, and and, as you say, the substitution turns that into which can be done with "integration by parts".
I would really appreciate if someone could check my methodology.Thanks.
describe the region in terms of the polar coordinates r and theta.
its is the region defined by x2+y2 less than or equal to 1 x≥0y≥0.
any suggestions ? I did the integral for r first ,where its boundary is from o to 1
theta varies from zero to pi/2
I made a u substituion where u=r^2 clearly du would be ...
I took x =rcosθ