I'm having trouble finding the extremas of... I'm having trouble finding the crit # of this. Please show me how to do it... f(x)= e^x/1-x+x^2
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Originally Posted by kwivo I'm having trouble finding the extremas of... I'm having trouble finding the crit # of this. Please show me how to do it... f(x)= e^x/1-x+x^2 This is I presume? Please use parenthesis! You will have critical numbers where , so solve So either <-- Doesn't happen or or So the critical points are x = 1 and x = 2. -Dan
Originally Posted by kwivo I'm having trouble finding the extremas of... I'm having trouble finding the crit # of this. Please show me how to do it... f(x)= e^x/1-x+x^2 To find local extrema, it is when the derivative is equal to zero. therefore local max or min occur at x=1 and/or x=2 Now look at the interval <1;at 1;1-2;at 2;>2 you will see that at x=1 it is a local max and at x=2 it is a local min
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