Re: surface integral problem

There is no **integral** here. What is the integrand and what surface are you integrating over?

Re: surface integral problem

Oh, I'm sorry, i wasn't clear enough. So, I need to integrate surface bounded with these curves.

So, when I sketch it, I have 1/4 of a circle, which is easy to integrate, then i need to find integral of a surface bounded with intersection of parabola and and y= 2^1/2 - x.

So I was thinking to solve it by splitting it in two parts, then integrating one plus the other.

Re: surface integral problem

I still have no clue what you mean. I have never heard of "integrating a surface". I have heard of integrating a given **function** over a surface or finding the area of a surface (equivalent to integrating 1 over the surface). Also, I am used to a "surface integral" as referring to a surface in **three** dimensions but your equations have only two variables, x and y. Is this in the xy-plane? Finally, I am confused by the fact that these curves divide the first quadrant into four separate regions. Which do you want to integrate over?

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Re: surface integral problem

Here, I attached a pic from a book i'm working from, too bad its not in eng, but you can see that formula with two integrals, thats the way we are finding surface of a 2-dim body. So, basic thing is we make two integrals dxdy and the first have constant boundaries and second have boundaries as functions in respect of x. And thats, in short, how we found surface of a 2-dim figure.

Got it?