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Math Help - work done by F-

  1. #1
    n22
    n22 is offline
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    work done by F-

    Hi,
    l am asking ..perhaps a stupid question ...nevertheless its important I get this right.
    Plz check methodology .
    Thanks.

    F=xyi-(2z^2)j+yzK
    Calcuate the work done by F along the straight line joining the points (1,0,0) and (2,2,3)

    This is what I did: set the parametric eqn using given points
    then gather x,,y,z in terms of t
    dr can be expressed in terms of t
    I used the followign parametric eqns :
    x=1+t
    y=2t
    z=3t

    anyhow,everything has to be in terms of t otherwise it cant be integrated.
    I integrated t :0 to 1

    finally I get something like -33 which is very wrong.
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  2. #2
    MHF Contributor
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    Re: work done by F-

    Hey n22.

    What did you get in terms of the integral (i.e. the function integrated should be <F,c> where <.,.> is the inner product)?
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  3. #3
    MHF Contributor

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    Re: work done by F-

    Those parameterizations will work. What did you get for the integral? Did you convert dx, dy, and dz into terms of dt also?
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