Results 1 to 2 of 2

Math Help - definite integrals question

  1. #1
    Member
    Joined
    Sep 2007
    Posts
    176

    definite integrals question

    p218 ex22a q25
    \left[\frac{1}{16}sinx\right]_{0}^{tan^{-1}\frac{3}{4}}= 0.0375 = <br />
\frac{3}{80}
    i can only do it by using calculator. i want to know if i can do it manually
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Apr 2005
    Posts
    1,631
    = (1/16)[sin(arctan(3/4) -sin(arctan(0)]

    arctan(3/4).
    opp side = 3
    adj side = 4
    So,
    hypotenuse = 5
    And so,
    sin(arctan(3/4)) = opp/hyp = 3/5

    arctan(0).
    opp side = 0
    adj side = 1
    So,
    hypotenuse = 1 -----actually, no hypotenuse.
    And so,
    sin(arctan(0)) = opp/"hyp" = 0/1 = 0 -----this is only for comparison.
    Of course, if tan(tetha) = 0, then theta = 0
    And sin(0) = 0 also.

    Hence,
    = (1/16)[3/5 -0]
    = 3/80
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 5
    Last Post: December 5th 2011, 06:21 PM
  2. Very simple question on "definite integrals"
    Posted in the Calculus Forum
    Replies: 4
    Last Post: August 17th 2011, 06:48 AM
  3. Replies: 4
    Last Post: April 13th 2011, 03:08 AM
  4. Strange question involving definite integrals
    Posted in the Calculus Forum
    Replies: 11
    Last Post: April 9th 2010, 01:34 PM
  5. Replies: 3
    Last Post: August 30th 2007, 03:03 PM

Search Tags


/mathhelpforum @mathhelpforum