# definite integrals question

• November 5th 2007, 12:57 AM
afeasfaerw23231233
definite integrals question
p218 ex22a q25
$\left[\frac{1}{16}sinx\right]_{0}^{tan^{-1}\frac{3}{4}}= 0.0375 =
\frac{3}{80}$

i can only do it by using calculator. i want to know if i can do it manually
• November 5th 2007, 01:26 AM
ticbol
= (1/16)[sin(arctan(3/4) -sin(arctan(0)]

arctan(3/4).
opp side = 3
So,
hypotenuse = 5
And so,
sin(arctan(3/4)) = opp/hyp = 3/5

arctan(0).
opp side = 0