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Math Help - derivative problem

  1. #1
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    derivative problem

    t = {n^2} + 2n\\
    dt = 2ndn + 2dn\\
    ddt = 2d{n^2}\\
    {d^3}t = 0


    i know how dt, {d^3}t is calculated but have no idea regarding ddt,..... what does it even mean
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  2. #2
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    Re: derivative problem

    Quote Originally Posted by mpx86 View Post
    t = {n^2} + 2n\\
    dt = 2ndn + 2dn\\
    ddt = 2d{n^2}\\
    {d^3}t = 0

    i know how dt, {d^3}t is calculated but have no idea regarding ddt,..... what does it even mean

    Your notation is awful.

    \\t=n^2+2n\\ \frac{dt}{dn}=2n+2\text{ first derivative} \\\frac{d^2t}{dn^2}=2\text{ second derivative}\\\frac{d^3t}{dn^3}=0\text{ third derivative}
    Thanks from mpx86 and topsquark
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  3. #3
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    Re: derivative problem

    Quote Originally Posted by Plato View Post
    Your notation is awful.

    \\t=n^2+2n\\ \frac{dt}{dn}=2n+2\text{ first derivative} \\\frac{d^2t}{dn^2}=2\text{ second derivative}\\\frac{d^3t}{dn^3}=0\text{ third derivative}

    i know this ......
    but i saw \[{\rm{ }}d(dt) = 2d{n^2}\] in a book and m curious to know how the author solved it...
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  4. #4
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    Re: derivative problem

    IMPLICIT FUNCTION. find dy /dx if xy-5x=3
    Thanks from mpx86
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  5. #5
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    Re: derivative problem

    derivative problem-24-jun-13.png
    Thanks from mpx86
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