$\displaystyle t = {n^2} + 2n\\$
$\displaystyle dt = 2ndn + 2dn\\$
$\displaystyle ddt = 2d{n^2}\\$
$\displaystyle {d^3}t = 0$
i know how dt, $\displaystyle {d^3}t$ is calculated but have no idea regarding ddt,..... what does it even mean
$\displaystyle t = {n^2} + 2n\\$
$\displaystyle dt = 2ndn + 2dn\\$
$\displaystyle ddt = 2d{n^2}\\$
$\displaystyle {d^3}t = 0$
i know how dt, $\displaystyle {d^3}t$ is calculated but have no idea regarding ddt,..... what does it even mean