# Showing that derivative tends to infinity (Poisson solution)

• Jun 21st 2013, 02:51 PM
algorithm
Showing that derivative tends to infinity (Poisson solution)
Hi,

In the plot below I have $f(\theta) = sin(\theta)$.

The second graph of the plot shows that, for x = 1, the plot of $P(\theta, x) = f(\theta - x f(\theta))$ has an infinite slope at $\theta = 0$ (called the Poisson non-linear propagation solution).

I'm trying to show this analytically but not getting the right answer. I reproduce my steps below.

We want to show that for $x = 1$, $P(\theta = 0, x)$ has an infinite slope, i.e. $dP/d\theta \rightarrow \inf$.

$P(\theta, x) = f(\theta - x f(\theta))$

we have $f(\theta) = sin(\theta)$, so

$P(\theta, x) = sin(\theta - x sin(\theta))$

$dP/d\theta = cos(\theta - sin(\theta))(1 - x cos(\theta))$

What I'm trying to show is $dP/d\theta \rightarrow \inf$, but that's clearly not possible from my result above.

Keen to hear where I'm going wrong. Thanks :)
• Jun 21st 2013, 05:37 PM
Re: Showing that derivative tends to infinity (Poisson solution)
Use the definition of a derivative at a point x=a. where the derivative of some function at a specified point is lim x->a (f(x)-f(a))/(x-a) to solve your problem
• Jun 21st 2013, 07:08 PM
topsquark
Re: Showing that derivative tends to infinity (Poisson solution)