chain rule of differentiating multi-variable functions:
du/(dx_1 )=∂u/(∂x_1 )+{∂u/(∂x_2 ) } (∂x_2)/(∂x_1 )=dk/(dx_1 )=0
Hello,
Can someone please explain how implicitly differentiating u(x_{1},x_{2}(x_{1})) = k with respect to x_{1} yields du(x_{1},x_{2})/dx_{1} + du(x_{1},x_{2})/dx_{2} * dx_{2}/dx_{1} = 0 ?
The textbook I'm reading just makes the statement and I'm not sure how it works out that way.
Thanks!