Hi, I was solving an integral and got this substitution

t= tg(x/2) then sin(x) = (2t)/(1+t^2) and cos(x) = (1-t^2)/(1+t^2)

How did I get sin(x) = (2t)/(1+t^2)?

I know that t = sinx/(cosx+1) and sinx = [(cosx+1)*t]

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