Finding the Line that Represents the Intersection of Two Planes

Suppose we have two intersecting planes, P1 and P2, whose normal vectors are n1 and n2, respectively. If one was asked to find the line of intersection, one could simply calculate $\displaystyle \vec{n}_1 \times \vec{n}_2 = \vec{u}$, of which $\displaystyle \vec{u}$ would be the direction vector for the line.

My question is, why is it the case that calculating the cross product of the normal vectors of the planes provides the direction vector?

Re: Finding the Line that Represents the Intersection of Two Planes

Quote:

Originally Posted by

**Bashyboy** Suppose we have two intersecting planes, P1 and P2, whose normal vectors are n1 and n2, respectively. If one was asked to find the line of intersection, one could simply calculate $\displaystyle \vec{n}_1 \times \vec{n}_2 = \vec{u}$, of which $\displaystyle \vec{u}$ would be the direction vector for the line.

My question is, why is it the case that calculating the cross product of the normal vectors of the planes provides the direction vector?

Because the line of intersection$\displaystyle ,~\ell,$ is perpendicular to each of the normals.

The vector $\displaystyle \vec{n}_1 \times \vec{n}_2 $ is perpendicular to each of $\displaystyle \vec{n}_1 ~\&~ \vec{n}_2 $.

Thus $\displaystyle \vec{n}_1 \times \vec{n}_2 = \vec{u}$ is the direction vector for $\displaystyle \ell$.

Re: Finding the Line that Represents the Intersection of Two Planes

So, the idea follows simply from a visual understanding?

Re: Finding the Line that Represents the Intersection of Two Planes

Quote:

Originally Posted by

**Bashyboy** So, the idea follows simply from a visual understanding?

I don't know how to respond to that statement.

Any line in a plane is perpendicular to the plane's normal.

Because $\displaystyle \ell$ is the line of intersection, it is in both planes, it is perpendicular to each of $\displaystyle \vec{n}_1 ~\&~ \vec{n}_2 $.

And that is $\displaystyle \vec{n}_1\times \vec{n}_2 $.

Re: Finding the Line that Represents the Intersection of Two Planes

Oh, wow, I didn't think about it in that sense, that the line of intersection lies in the plane. Obviously that makes sense: for if it wasn't, then the coordinates on the line wouldn't satisfy the equation of the plane, and vice-versa.