When it's difficult to solve for y, then we can use implicit differentiation.
Solve for dy/dx:
Now, find the slope at x=3
Hey... i have no idea how to work with the y's in the equation. '
The question is:
Determine the equation of the tangent line to the graph of the relation with equation xy^2+x^2y=12 at the point where x=3.
Please any help would be greatly appreciated... thanks
most excellent.. took me a while to understand what was going on but i got it now... however, i don't get how to find the slope!!! I can't isolate the y...
and i have to find where x=3...
if i try to plug it into the original equation - can't isolate y
when i try the derivative - still can't isolate y
how do i go about isolating the y because i get what to do afterwards it's this y that is not making sence to me!!!
thanks