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Math Help - surface A-calculus for upcomingexam

  1. #1
    n22
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    surface A-calculus for upcomingexam

    Hi,
    I am having issues here.thanks
    Determine surface A such that
    ∫∫s(∇xF).nds =∫∫A(∇xF).kda
    explain why inequality holds
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  2. #2
    MHF Contributor
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    Re: surface A-calculus for upcomingexam

    Hey n22.

    Consider a flat surface.
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  3. #3
    MHF Contributor

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    Re: surface A-calculus for upcomingexam

    Quote Originally Posted by n22 View Post
    Hi,
    I am having issues here.thanks
    Determine surface A such that
    ∫∫s(∇xF).nds =∫∫A(∇xF).kda
    explain why inequality holds
    I am confused as to what you mean here. Is "n" the unit normal to surface S and "k" the unit normal to surface A?

    Apparently you are to find a surface, "A", so that the integral of \nabla\times F over A is the same as the integral over S? What is "S"? Wouldn't it be simplest to take A= S?

    And, since you have "=" between those two integrals, what does "explain why inequality holds" mean?
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  4. #4
    n22
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    Re: surface A-calculus for upcomingexam

    Quote Originally Posted by HallsofIvy View Post
    I am confused as to what you mean here. Is "n" the unit normal to surface S and "k" the unit normal to surface A?

    Apparently you are to find a surface, "A", so that the integral of \nabla\times F over A is the same as the integral over S? What is "S"? Wouldn't it be simplest to take A= S?

    And, since you have "=" between those two integrals, what does "explain why inequality holds" mean?
    yes.you are correct theres nothing to be confused about.
    Am I just proving that LHS=RHS?
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