Hi,

I am having issues here.thanks

Determine surface A such that

∫∫_{s}(∇xF).nds =∫∫_{A}(∇xF).kda

explain why inequality holds

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- Jun 12th 2013, 04:34 AMn22surface A-calculus for upcomingexam
Hi,

I am having issues here.thanks

Determine surface A such that

∫∫_{s}(∇xF).nds =∫∫_{A}(∇xF).kda

explain why inequality holds - Jun 12th 2013, 04:39 AMchiroRe: surface A-calculus for upcomingexam
Hey n22.

Consider a flat surface. - Jun 12th 2013, 08:17 AMHallsofIvyRe: surface A-calculus for upcomingexam
I am confused as to what you mean here. Is "n" the unit normal to surface S and "k" the unit normal to surface A?

Apparently you are to find a surface, "A", so that the integral of over A is the same as the integral over S? What is "S"? Wouldn't it be simplest to take A= S?

And, since you have "=" between those two integrals, what does "explain why**in**equality holds" mean? - Jun 12th 2013, 10:23 PMn22Re: surface A-calculus for upcomingexam