# surface A-calculus for upcomingexam

• Jun 12th 2013, 04:34 AM
n22
surface A-calculus for upcomingexam
Hi,
I am having issues here.thanks
Determine surface A such that
∫∫s(∇xF).nds =∫∫A(∇xF).kda
explain why inequality holds
• Jun 12th 2013, 04:39 AM
chiro
Re: surface A-calculus for upcomingexam
Hey n22.

Consider a flat surface.
• Jun 12th 2013, 08:17 AM
HallsofIvy
Re: surface A-calculus for upcomingexam
Quote:

Originally Posted by n22
Hi,
I am having issues here.thanks
Determine surface A such that
∫∫s(∇xF).nds =∫∫A(∇xF).kda
explain why inequality holds

I am confused as to what you mean here. Is "n" the unit normal to surface S and "k" the unit normal to surface A?

Apparently you are to find a surface, "A", so that the integral of $\nabla\times F$ over A is the same as the integral over S? What is "S"? Wouldn't it be simplest to take A= S?

And, since you have "=" between those two integrals, what does "explain why inequality holds" mean?
• Jun 12th 2013, 10:23 PM
n22
Re: surface A-calculus for upcomingexam
Quote:

Originally Posted by HallsofIvy
I am confused as to what you mean here. Is "n" the unit normal to surface S and "k" the unit normal to surface A?

Apparently you are to find a surface, "A", so that the integral of $\nabla\times F$ over A is the same as the integral over S? What is "S"? Wouldn't it be simplest to take A= S?

And, since you have "=" between those two integrals, what does "explain why inequality holds" mean?

yes.you are correct theres nothing to be confused about.
Am I just proving that LHS=RHS?