If it weren't for that "n" at the beginning, that would be a geometric series. But that n makes me think of a derivative. If we set then . Does that give you any ideas?
Thanks for the reply ..
So you're saying that I could at first find the sum
and I get the function f(z)
and just count the derivative of f'(z) ?
this series looks not as difficult as the first one, but I still can't find the sum ..
would you please give me another hint?
okey,
can you please explain how does the geometric series work for complex numbers?
I dealt only with real geometric series and the sum is then easy
is there any sum formula for complex terms?
in my series number
thank you
Hello, alteraus!
I think I found the sum.
But check my work . . . please!
I found out that the series converges for ,
but I am not able to find the sum of the series.
. . . . . . . . . .
The geometric series has first term and common ratio
. . Its sum is: .
We have: .
. . . . . . . . . . . . . .
. . . . . . . . . . . . . .