Integral sin(3x pi/a)sin(2x pi/a)cos(x pi/a)
I'm doing a bit of quantum mechanics and I'm doing a question on the infinite square well.
Anyway, I'm a bit stuck on this integral:
Does anyone know how to integrate this?
I tried reversing the product rule for 3 functions and got this:
But I didn't really get anywhere.
I know that these functions are orthogonal to each other (except for the cosine) and so if they were all sines I can use the Kronecker Delta function to evaluate them faster, but that cosine really messes things up.
Using Wolfram Alpha I got but I want to know how to do this.
Re: Integral sin(3x pi/a)sin(2x pi/a)cos(x pi/a)
remember the sum and product formula for trig functions.
2 sinAsinB = cos(A-B) - cos ( A+B)
2 cosAcosB = cos(A+B) + cos ( A-B)
2 sinAcosB = sin(A+B) + sin ( A-B)
2 cosAcosB = sin(A+B) - sin ( A-B)
Apply the appropriate one and you will have your integral reducing to simple integral of trig ratios