the value of
C. a-b (which I think is right)
E. b-a (might be true?)
I am confused because the last integral boundaries are from 0 to -1 and I always see them written from the smaller to the bigger number, aka from -1 to 0.
Does this makes a the result different? (maybe it's a mistake in the printing?)
attached image is another question, sorry for the unprofessional editing, it's from the book and it's not in English so i had to edit it a little... the pen markings are my own, what I think are correct/incorrect.
So I basically think statements 2 and 3 are correct, therefore answer D would be my choice, what do you think?
I need to send this out today and have total of 18 problems to answer (luckily this time they are multiple choices, not "open ended")
I would probably add more pictures as it's much easier and faster than typing the whole equations in the forum...
Attached image is another question.
So I basically think statements 2 and 3 are correct.
Therefore, answer D would be my choice. .What do you think? . I agree!
The graph of is continuous and passes throughCode:| * | * | |::* | |::::* 4 --+---+------*----+---- | 1 3*:::| | *:| | *
= shaded area.
is the antiderivative of
Which are the correct statements?
Statement 1 is incorrect.
The integral from 1 to 4 is not the shaded area.
It is the net area (some of which is negative).
Statement 4 is equivalent to statement 1.
It is also incorrect.
Statement 2 is correct.
It gives the value of the definite integral.
Statement 3 is correct.
The total shaded area is the integral from 1 to 3
. . minus the integral from 3 to 4.
Given the function , R is a constant.
Find the anti derivative F(x) that such that F(R) = 0.
What is the value of F(0.5R)+F(2R)+F'(0.5R)+F'(2R)?
I tend to go with C because I somehow got to 3/2R after calculating only the F'(0.5R)+F'(2R) (these are just the given function right?)
But I have a feeling the F(0.5R)+F(2R) will change it to something else...also where does the 0.19 comes from I wonder.