Stationary point of inflection
I have this question that I have been looking at for hours and I'm well and truly over it.
Would like some help please.
Obviously it's linked to Derivatives and Concavity, but I'm not sure how to go about it.
Thanks for your time.
Re: Stationary point of inflection
I would let the quadratic function be:
Now, require and and you will get two equations from which you will be able to solve for and , where remains a parameter, as it merely shifts the function vertically and so has no bearing on the -coordinate of critical values.