No - they range between 0 and 2 pi.
From de Moivre's formula,
, the angle
of one solution will be 1/n the angle of z. Note that I like to use the notation "cis theta" (pronounced "kiss theta") as shorthand for
. But since cosine and sine functons have a period of
, other solutions are available that are "evenly spaced" about the origin separated by the angle
. In this way there are always n solutions to the nth root of z.
Let me give an example: If z = 16i, which is equal to
, there are four 4th roots. The magnitude of z is 16, so the magnitude of the 4th roots are all
. The angle of the first solution is at angle
, and the rest are at
, where k = 0, 1, 2, and 3. Thus the four 4th roots of 16i are:
.
Now, can you apply this thinking to the problem at hand?