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Originally Posted by afeasfaerw23231233 integration no.7
Does this help?
i know how to do it now , thanks!
The denominator (1 +sin^2(theta)) is not (1 +u^2) because u = cos(theta).
= 1 +1 -cos^2(theta)
= 2 -cos^2(theta)
= 2 -u^2
So it must be
INT.[(1 -4u^2) / (2 -u^2)]du
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