Hey all, I was wondering if you could help me? How do you intergrate the function (1-sin^2x)? I'm really lost with the whole intergration of cos^2x and sin^2x Thanks
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$\displaystyle \displaystyle\int(1-\sin^2x)dx=\int\cos^2xdx=\int\frac{1+\cos 2x}{2}dx$ Now, continue from here.
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