# Math Help - Intergration of trig function (1-sin^2x)

1. ## Intergration of trig function (1-sin^2x)

Hey all,
I was wondering if you could help me?
How do you intergrate the function (1-sin^2x)?
I'm really lost with the whole intergration of cos^2x and sin^2x
Thanks

2. $\displaystyle\int(1-\sin^2x)dx=\int\cos^2xdx=\int\frac{1+\cos 2x}{2}dx$
Now, continue from here.